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Mathematics 10 Online
OpenStudy (anonymous):

Use the method of quadrature to estimate the area under the curve y= -3/5x^2 =7 that is above the x-axis from x = 0 to x = 2.

ganeshie8 (ganeshie8):

Is this the curve : y= -3/5x^2 + 7 ?

OpenStudy (anonymous):

Yeah sorry I was typing fast.

ganeshie8 (ganeshie8):

okay :) you just need to count the "number of squares" under the curve. have u graphed it already ?

OpenStudy (anonymous):

No. let me get my calculator (:

ganeshie8 (ganeshie8):

calculator may not be good to visualize/count squares. graph it in geogebra/desmos maybe....

OpenStudy (anonymous):

I counted 7 but that isn't one of the answers

ganeshie8 (ganeshie8):

ganeshie8 (ganeshie8):

^ there is the graph, green is the area u want to estimate.. . count agian :)

OpenStudy (anonymous):

so it's 12.2?

ganeshie8 (ganeshie8):

looks good... something between 12 and 13 mostly..

OpenStudy (anonymous):

Ok thank you (:

ganeshie8 (ganeshie8):

np :)

OpenStudy (anonymous):

Have a nice night/afternoon/morning! (:

OpenStudy (anonymous):

But one more question please?

ganeshie8 (ganeshie8):

ty :D you too !

ganeshie8 (ganeshie8):

yeah... shoot :)

OpenStudy (anonymous):

Can you please explain the method?

ganeshie8 (ganeshie8):

method of quadrature ?

OpenStudy (anonymous):

Yes please (:

ganeshie8 (ganeshie8):

sure :) the name just sounds fancy... but the method is very basic

ganeshie8 (ganeshie8):

you measure ur house area in terms of "square fee", right ?

OpenStudy (anonymous):

Yep.

ganeshie8 (ganeshie8):

|dw:1397816610895:dw|

ganeshie8 (ganeshie8):

Suppose you can fit 200 "square tiles" in ur house area.

ganeshie8 (ganeshie8):

what will be the area of land occupied by ur house ?

ganeshie8 (ganeshie8):

|dw:1397816696276:dw|

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