Mathematics
10 Online
OpenStudy (anonymous):
Use the method of quadrature to estimate the area under the curve y= -3/5x^2 =7 that is above the x-axis from x = 0 to x = 2.
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ganeshie8 (ganeshie8):
Is this the curve :
y= -3/5x^2 + 7
?
OpenStudy (anonymous):
Yeah sorry I was typing fast.
ganeshie8 (ganeshie8):
okay :) you just need to count the "number of squares" under the curve.
have u graphed it already ?
OpenStudy (anonymous):
No. let me get my calculator (:
ganeshie8 (ganeshie8):
calculator may not be good to visualize/count squares.
graph it in geogebra/desmos maybe....
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OpenStudy (anonymous):
I counted 7 but that isn't one of the answers
ganeshie8 (ganeshie8):
ganeshie8 (ganeshie8):
^ there is the graph,
green is the area u want to estimate.. .
count agian :)
OpenStudy (anonymous):
so it's 12.2?
ganeshie8 (ganeshie8):
looks good...
something between 12 and 13 mostly..
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OpenStudy (anonymous):
Ok thank you (:
ganeshie8 (ganeshie8):
np :)
OpenStudy (anonymous):
Have a nice night/afternoon/morning! (:
OpenStudy (anonymous):
But one more question please?
ganeshie8 (ganeshie8):
ty :D you too !
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ganeshie8 (ganeshie8):
yeah... shoot :)
OpenStudy (anonymous):
Can you please explain the method?
ganeshie8 (ganeshie8):
method of quadrature ?
OpenStudy (anonymous):
Yes please (:
ganeshie8 (ganeshie8):
sure :) the name just sounds fancy... but the method is very basic
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ganeshie8 (ganeshie8):
you measure ur house area in terms of "square fee", right ?
OpenStudy (anonymous):
Yep.
ganeshie8 (ganeshie8):
|dw:1397816610895:dw|
ganeshie8 (ganeshie8):
Suppose you can fit 200 "square tiles" in ur house area.
ganeshie8 (ganeshie8):
what will be the area of land occupied by ur house ?
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ganeshie8 (ganeshie8):
|dw:1397816696276:dw|