Write an equation of the parabola with the vertex at (5,-3) and focus at (1,-3) @ganeshie8
(y-k)^2=4p(x-h)
First, figure out whether it faces UP-DOWN, or LEFT-RIGHT
left and right?
cuz the foci
Correct ! its a left and right since the y coordinate is fixed
and you know vertex already, so the equation will look like : \(\large (y-(-3))^2=4p(x-5)\) right ?
you just need to find the value of \(\large p\)
yes
wait so is that it for the equation cuz its only asking for the equation
you still need to find the value of \(\large p\) p = focus - vertex = 1 - 5 = -4
so, the equation wud be : \(\large (y-(-3))^2=4(-4)(x-5) \)
simplify
ok
would it be y+3? or do i just leave it like that
either way is fine...
\(\large (y-(-3))^2=4(-4)(x-5)\) is same as : \(\large (y+3)^2=-16(x-5)\)
Join our real-time social learning platform and learn together with your friends!