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OpenStudy (ammarah):
Graph
(x+4)^2=-8(y-2)
Parabola?
Vertex: (-4,2)
Directrix:y=2??
Please check my answers @ganeshie8
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ganeshie8 (ganeshie8):
its a parabola cuz you have only one square term
ganeshie8 (ganeshie8):
vertex is right
ganeshie8 (ganeshie8):
directrix looks wrong
ganeshie8 (ganeshie8):
check again
ganeshie8 (ganeshie8):
\(\large (x+4)^2=-8(y-2)\)
compare wid standard form :
\(\large (x-h)^2=4p(y-k)\)
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ganeshie8 (ganeshie8):
\(\large 4p = -8 \implies p = -2\)
right ?
OpenStudy (ammarah):
yes y=-2?
ganeshie8 (ganeshie8):
Directrix : \(\large y = k-p\)
OpenStudy (ammarah):
-4
ganeshie8 (ganeshie8):
you should get :
Directrix : \(\large y = 2 --2 \implies y = 4\)
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OpenStudy (ammarah):
ok can u show me how the graph looks like....idk what points to plug in
ganeshie8 (ganeshie8):
just sketch it roughly
ganeshie8 (ganeshie8):
first plot vertex and directrix
OpenStudy (ammarah):
|dw:1397826931867:dw|
ganeshie8 (ganeshie8):
Excellent !
and you must be knowing that the parabola always opens toward Focus.
and Focus will be on mirror opposite side of directrix
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OpenStudy (ammarah):
how do u find the focus?
ganeshie8 (ganeshie8):
|dw:1397827016744:dw|
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