Can Someone Help Me ? Algebra 1 i'll Metal && Fan (:
are you related to rob dyrdek
Lol i get that alot, no
i say the answer is a oh and lol srry
i need to know for sure lol this improtant
@mathslover
a
a?
nate look at the attachment
i did :)>
:-)
@whpalmer4 can you help me? i was thinking a , or B
Let's go through the answers one by one. "It is decreasing in the interval \(2 < x < 4\)" That is only partly true. From \(x = 2 \text{ to } x=3\), the \(y\) value of the graph (which represents the velocity at time \(x\)) is indeed decreasing, which shows decreasing velocity. However, what happens from \(x=3 \text { to } x=4\)? The \(y\) value increases, so velocity is increasing, and the statement above is not true. Scratch A.
The second answer choice is "It is decreasing in the interval \(3 < x < 4\)" Uh, problem author, weren't you paying attention? We just demonstrated that it is increasing in that very interval, and that's why A wasn't a correct answer choice. Turns out B isn't a correct answer choice, either, and we didn't have to do any more work to determine that :-)
Now, hopefully that gives you enough information to make the correct choice between C and D.
C ? >.<
wow :0
Tell me why you choose C.
(don't now change your answer to D because I asked that question — I would ask that question regardless of which choice you make!)
No actually i do want to change my answer to D.
you said " However, what happens from x=3 to x=4? The y value increases, so velocity is increasing,"
u could have just said d
but he wanted me to explain lol
Okay, d is a good choice :-) Here's a hint: explaining something to someone else is a good way to solidify your understanding. That's why I ask people to do that when they choose an answer.
So D, is right? Thank you!
Yes, D is correct. Overall, the velocity is constant from x = 0 to x = 2. Then it decreases from x = 2 to x = 3, increases from x = 3 to x = 4, and is once again constant from x = 4 to x=6. At that point, the person walks into a lamp post and falls to the ground, unconscious :-)
Sometimes you have to read between the lines a bit, but I'm pretty sure that's what happens at x = 6 :-)
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