Question

please explain this piece of code

#include #include int main () { int ch; ch=getch(); printf("%d",ch); printf (" %d", getch ()); return 0; }

Answer 1

whoever explains me this to my satisfaction level gets a gold medal

Answer 2

int ch; \\ just declaring int variable
ch=getch(); \\ means read any single character from the keyboard but that character will not be seen in the screen .

printf("%d",ch); \\ basically print the integer value of ch if there's integer in ch %d otherwise nothing .

printf (" %d", getch ()); \\ I guess <I'm not sure> read again from the keyboard and if it's integer print it otherwise nothing

Answer 3

%d means print the integer in the string that in the second location in the printf function

Answer 4

printf (" %d", getch ()); \\ its not reading again from the keyboard instead its displaying some number. run it and see

Answer 5

look at first ch=getch();

will take anycharacter from keyborad and put it in ch (converted to it ascii code)

so when you write for ex. in first getch()

A from keyborad it will convert to it ascii code which is 65
http://www.asciitable.com/

when u write 5 for ex. will be 53 (ascii code for 5 )

u get it ?

Answer 6

```
/* scode.c a
* converts the first two charecters of input to ASCII code numbers
* Example: ./scode
Aa
--> 65 97
*/

//#include <conio.h> // console input-output library [only for Windows]
#include <cs50.h> // computer science 50 library [has getchar instead of getch]
#include <stdio.h> // standard input-output library


int main()
{
int ch; // declares an integer 'ch'
ch = getchar(); // sets 'ch' to the first charecter typed by user
printf("%d", ch); // prints the integer that 'ch' corresponds in ASCII code

printf(" %d", getchar()); // prints a space then the integer for the second charecter typed

return 0; // quits
}
```

for reference ASCII code