Question

@hartnn Can you help with this one, i tried what you said , but im not good with the fractions

Answer 1

this is different type of question,
if you read, they want a PERPENDICULAR line

Answer 2

can you find the slope of this line first ?

Answer 3

2

Answer 4

no, thats the y-intercept
for the slope, you need 2 points on that line
can you identify any 2 points on that line ?

Answer 5

-4, and 6 ?

Answer 6

one of the easy points is 0,2 because when x=0, y=2

Answer 7

okay (:

Answer 8

and other point ?
how about -3,-2
does that lie on the line ?

Answer 9

and since you have 2 points now, you can use the famous slope formula

The slope of the line through points (x1,y1) and (x2,y2) is given by :
\(\huge m=\frac{y_1-y_2}{x_1-x_2}\)
now,just put the values and find m.

Answer 10

in your case,
x1 = 0, y1= 2
x2 = -3, y2 = -2

Answer 11

im so lost

Answer 12

you have any doubts that -3,-2 is a point lying on our line ?
check it....

Answer 13

yes

Answer 14

now to fnd the slope we need atleast 2 points which we have.
use the slope formula to get the slope m

Answer 15

The slope of the line through points (x1,y1) and (x2,y2) is given by :
\(\huge m=\frac{y_1-y_2}{x_1-x_2}\)
now,just put the values and find m.
x1 = 0, y1= 2
x2 = -3, y2 = -2
plug in!

Answer 16

4/3 ?

Answer 17

sorry, i interchanged the co-orinates of 2nd point
the 2nd point is
-2,-3

x1 = 0, y1= 2
x2 = -2, y2 = -3
plug this in

Answer 18

5/2

Answer 19

thats correct!
now to get the slope of perpendicular line, you need to take the negative reciprocal of this slope.

example, if my slope is a/b, then slope of perpendicular line will be -b/a

Answer 20

so its -2/5

Answer 21

so its c ?

Answer 22

correct!
thats your slope = m
and y intercept =c= was already 2, we found.
just plug this in the equation of line
\(\large y= mx+c\)

Answer 23

yes, sorry, c was not 2
and yes
its C :)