write an equation of the line. (0,3) 7x+3y=2
I don't understand the question. (0, 3) is a point. 7x + 3y = 2 is the equation of a line. What exactly is the problem asking for?
it says....write an equation of the line containing the given point and perpendicular to the given line.
@mathstudent55
can you find the slope of the line 7x+3y = 2 ?
-7/3
thats correct! did you know that product of slope of perpendicular lines = -1 ?
no
now i do lol
now you know m*(-7/3) = -1 find m from here :)
wait huh? i dont understand.
say the slope is a/b then the slope of perpendicular line will be -b/a or "the negative reciprocal"
so it would be 7/3=-1
the slope of line was -7/3 so the slope of perpendicular line will be +3/7 i interchanged the numerator and denominator (reciprocal) and inverted the sign
so how would i find the equation of the line?
y=
now you have the slope m = 3/7 and a point x1,y1 = 0,3 just plug these in \(y-y_1 = m (x-x_1)\)
y-3=3/7(x-0)
correct! now simplify
y=3x/7+3
y-3= 3x/7 multiply 7 on both sides first
21-3=3x/7
7(y-3) =3x 7y -21 = 3x 7y-3x = 21
so how would i turn that into y=mx+b format?
oh, u need it into y=mx+b format ? then y =(3/7)x+3 was correct :)
do i usethe parenthesis?
yes, you can but both y= (3/7)x+3 and y= 3x/7 + 3 are correct. though the second on is bit confusing
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