Question

Travis is riding the Ferris wheel at the amusement park. His height can be modeled by the equation
H(t) = 22 cos π/13t + 28, where H represents the height of the person above the ground in feet at t seconds.

Part 1: How far above the ground is Travis before the ride begins?
Part 2: How long does the Ferris wheel take to make one complete revolution?
Part 3: Assuming Travis begins the ride at the top, how far from the ground is the edge of the Ferris wheel, when Travis' height above the ground reaches a minimum?

Answer 1

H(t) = 22 cos[(pi/13)t] + 28 seems to be the expression

H(t=0) = 22 + 28 = 50 feet up at start? yes, see part 3

One revolution: (pi/13) t = 2 pi solve for t

lowest point is when cos = -1, calculate H(t) then