evaluate the integral from 1 to 2 ((v^4+3v^5)/(v^3)) dv
I am really struggling with this.

Question

anonymous · Answer

your pic is so adorable

anonymous · Answer

I have gotten (v+3v^2)dv=[(1/2)v^3+v^4] I don't know what to do from there

anonymous · Answer

sweetie i am sorry i have an f on math!

anonymous · Answer

okay thank you though

zepdrix · Answer

$$\Large\rm \int\limits_1^2 \frac{v^4+3v^5}{v^3}dv=\int\limits_1^2 \frac{v^4}{v^3}+\frac{3v^5}{v^3}dv$$$$\Large\rm \int\limits_1^2 v+3v^2\;dv=\frac{1}{2}v^2+\frac{3}{3}v^3|_1^2$$Hmm I think your powers might be off a little bit

anonymous · Answer

and then from there I just use the 1 and 2 in that?

zepdrix · Answer

Yes :)
Upper minus lower.
If it helps to remember which comes first, think of it like old school subtraction:|dw:1397855878670:dw|