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A light ray travels from water (n = 1.33) to crown glass (n = 1.52) and bends at a 30º angle to the normal. What is the incident angle for the light from the water? Answer with three significant digits. **I tried Snell's Law and no matter what I do, I didn't get the correct answer, help me :(
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It seems like you have all the information for Snell's Law!|dw:1397869962800:dw| \(n_w\sin\theta_w=n_g\sin\theta_g\) \(\implies \theta_w=\arcsin\left(\dfrac{n_g\sin\theta_g}{n_w}\right)\)
|dw:1397870541728:dw| That doesn't seem too bad :) What are you getting?
Good luck! If you're using a calculator, make sure you have it set to degrees!
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