Question

solve for right triangle ABC with the given parts a=6, b=7

Answer 1

Can you draw a picture to start please?

Answer 2

Good, so now, what theorem do we know about right triangles?

Answer 3

Hint: it is very famous

Answer 4

the Pythagorean theorem

Answer 5

good and what is the pythagorean theorem?

Answer 6

\[a ^{2} + b ^{2} =c ^{2}\]

Answer 7

alright, and what does c represent?

Answer 8

the hypotenuse

Answer 9

good so now, can you input your values into the pythagorean thm?

Answer 10

\[7^{2} + 6^{2} = c ^{2}\]

Answer 11

good, so now, can you simplify the left side?

Answer 12

49+36=[c ^{2}\]

Answer 13

good good now combine like terms

Answer 14

\[85=c ^{2}\]

Answer 15

\[\sqrt{85}=\sqrt{c}\]

Answer 16

check that last step

Answer 17

\[\sqrt{85}=C ^{2} \] ?

Answer 18

that one?

Answer 19

Yea, that step is not correct

Answer 20

so you are taking the square root of both sides right?

Answer 21

yeah

Answer 22

so can you tell me what the square root of something squared is?

Answer 23

i dont know but i thought it would cancel out as in
\[\sqrt{85} = \sqrt{C ^{2}}\]

Answer 24

and then

\[\sqrt{85} = C\]

Answer 25

yep, that is right now

Answer 26

but how can i get \[\sqrt{85}\]

Answer 27

oh that's the answer, unless you want to try and simplify it, but I'd just leave that as is

Answer 28

oh ok so then am i supposed to solve for the angles

Answer 29

Well, I mean you could if you have learned the trig functions, but usually it just means to find all of the sides

Answer 30

yeah i did but im confused on how to solve for the angles

Answer 31

well, what is the definition of tangent?

Answer 32

opposite over adjacent

Answer 33

good so label the angles A and B, what is tan A? tanB?

Answer 34

but how will i know what is the opposite or adjacent when im not given any other number

Answer 35

oh just label whichever you want A and the other B, that's all the info you require

Answer 36

oh ok

Answer 37

did you get it?

Answer 38

lol....no

Answer 39

show me your work?