Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Explain the process where: X = 16^(3/2) X = (root 16)^3

OpenStudy (anonymous):

OpenStudy (anonymous):

First we have to split power of 16 can you try ?

OpenStudy (anonymous):

oh, no I already know how to do it... its just I don't understand why the denominator becomes 2 root and why the numerator becomes the power

OpenStudy (anonymous):

okay let me explain it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

We were having x^(2/3) = 16 We have to solve it for x so need to reduce power of x to one

OpenStudy (anonymous):

Getting this ???

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

okay So here we have to use reciprocal of power like if fraction is like a/b then its reciprocal is b/a so what would be reciprocal of power of x which is ( 2 / 3 ) ?

OpenStudy (anonymous):

\[\frac{ 3 }{ 2 }\]

OpenStudy (anonymous):

correct so we need to take ( 3/2 ) power on both sides So we get x^( 2/3) * ( 3/2) = 16^(3/2) So it becomes x = 16^( 3 / 2 ) getting this ???

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

Now we need to split power of 16 using rule of multiplication of power Are you familiar with rule a^( m)*( n ) = a^ m * n ?

OpenStudy (anonymous):

See the attachment.

OpenStudy (anonymous):

oh,ok

OpenStudy (anonymous):

Are you getting this ? So we can rewrite it as 16^ ( 3 ) * ( 1/2 ) correct ?

OpenStudy (anonymous):

Yeah

OpenStudy (anonymous):

16^(1/2)*(3) So first we would find out 16^( 1/2) = ---- ? what is square root of 16 ?

OpenStudy (anonymous):

4

OpenStudy (anonymous):

Perfect So we get 16^((1/2) * 3) = 4^3 = ----- ? So 4 cube = ----- ???

OpenStudy (anonymous):

We are about to finish it last step 4^3 = ---- ?

OpenStudy (anonymous):

64

OpenStudy (anonymous):

Awesome Is it clear to you now ?

OpenStudy (anonymous):

oh you know what I just remembered that \[\sqrt[2]{?}\] is the same thing as saying \[(?)\frac{ 1 }{ 2 }\]

OpenStudy (anonymous):

yes correct you are right it would be ? ^ ( 1/2 )

OpenStudy (anonymous):

so you just converted to a format that you could use... lolz

OpenStudy (anonymous):

yes Is it clear now ?

OpenStudy (anonymous):

yeah, thanks for explaining it to me.

OpenStudy (anonymous):

You are most welcome :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!