Question

How do I find the range of a parametric equation?

Answer 1

The parametric equation is given by x(t)=sin(t^2) and y(t)=2t+1 for values of t greater than or equal to 0 and less than or equal to pi

Answer 2

Well, it's like finding the range of a regular function.
You know a regular sine function has a range from -1 to 1. It's also the case here.
x(t) goes from sin(0) to sin(pi^2), so it goes from -1 to 1 at some point.

y(t) is a linear function, so the range will be what the values at t=0 and t=pi are.

Answer 3

That was easier than I expected it to be! thank you.