prove the identity is true (1-cos^2x)cotx=sinxcosx
Hi, do you have an identity sheet that has Pythagorean identities on it?
Can you tell me what \[1-\cos ^{2}x \] equals?
@hconejo100
sin^2x
and what does cotx also equal is it... \[\frac{ cosx }{ sinx }\] ?
yes
So lets see what we have...
\[\sin ^{2}x(\frac{ cosx }{ sinx })\]
which simplifies to... \[\frac{ \sin ^{2}xcosx }{ sinx } = sinxcosx\]
Make sense?
not really
What step does not make sense?
well it does makes sense but on my homework i have to prove it by writing it step by step and what rule is each step
\[1 - \cos ^{2}x = \sin ^{2}x\] is substitution
\[cotx = \frac{ cosx }{ sinx }\] Substitution
\[\sin ^{2}x(\frac{ cosx }{ sinx })\] Multiplication
\[\frac{ \sin ^{2}xcosx }{ sinx } = sinxcosx\] Simplifying
better @hconejo100 ?
the rules i can chose from are -algebra -reciprocal -quotient -Pythagorean -odd/even here is an example my teacher gave me cotx/cscx-1=cscx+1/cotx to prove it he put =cotx/cscx-1*cscx+1/cscx+1 Algebra =cotx(cscx+1)/csc^2x-1 Algebra =cotx(cscx+1)/cot^2x Pythagorean =cscx+1/cotx algebra
1st = Pythagorean 2nd = Reciprocal 3rd =Algebra 4th = Quotient
thanks for your help
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