Please help me
The rectangles are similar. The length of the larger rectangle is 3x + 1 and the width is 8. The length of the smaller rectangle is 5 and the width is 4. What is the length of the larger rectangle?
I got 3 but that does't seem to be reasonable
well from looking at this we know that the width of the larger rectangle is 8, and the width of the smaller one is 4, we also know that half of 8 is 4, so that gives us a good head start :) Now since the length of the larger is unknown well make it x, and the length of the smaller rectangle is 5. so now we would do 5+5 and get 10 I think
I don't know
@mathmale what do you think
The rectangles are similar. The length of the larger rectangle is 3x + 1 and the width is 8. The length of the smaller rectangle is 5 and the width is 4. What is the length of the larger rectangle? Wasn't there an illustration with this problem, Daniel?
Yes sir https://s3.amazonaws.com/algebranation/testyourself_uploads/images4/4.2.2.jpg
If not, we can still solve this problem without an illulstration. I will re-draw the 2 rectangles and add the given dimensions:
https://s3.amazonaws.com/algebranation/testyourself_uploads/images4/4.2.2.jpg
|dw:1398012690402:dw|
Daniel, think of what y ou might do next. I'll be back in a minute or two. (Hint: write and equate ratios).
\[\frac{ 3x+1 }{ 8 }*\frac{ 5 }{ 4 }\]
I did that and i got 3... x=3
You're doing fine!
Comfortable with this one?
So it is 3?
@mathmale
Yes indeed. I should have said YES up front, instead of "You're doing fine."
Thanks
And thank you too!!
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