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limit question as h approaches 0
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\[\frac{ e^(a+h) -e^a }{ h }\]
that should be e to the (a+h) power
^{a+h}
use that latex.
\[\frac{ e^{a+h}-e^a }{ h }\]
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\[\large\frac{e^{a+h}-e^n}{h}\]
sorry I don't know latex but I use the the braces. Don't forget the second term is e^a
I factored out e^a
not sure what to do, I sub h=0 and I got e^a (0/0)
\[\huge\lim_{h \rightarrow 0}~ \frac{e^{a+h}-e^{a} }{h}\]
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I was told the solution is e^a but I don't know how
does 0/0 cancel out? but I thought 0/0 is undefined
I have a Ti-89, I don' t know how to input a limit, it does do limits. The worksheet is suppose to be done with a graphing calculator but I don't know how to do this limit.
I can't get farther than |dw:1398038315983:dw|
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