Reduce the following rational expression to lowest terms, if possible. (If not possible, enter IMPOSSIBLE.) 3x − 9 4x − 16
It's a fraction.
\(\dfrac{3x - 9}{4x - 16} = \dfrac{3(x - 3)}{4(x - 4)}\) \(=\dfrac{3}{4} \dot\ \dfrac{x - 3}{x - 4}\) \(=\dfrac{3}{4} \dot\ \dfrac{x - 4 + 1}{x - 4}\) \(=\dfrac{3}{4} \left( \dfrac{x - 4}{x - 4} + \dfrac{1}{x - 4}\right)\) \(=\dfrac{3}{4} \left( 1+ \dfrac{1}{x - 4}\right)\) \(=\dfrac{3}{4} + \dfrac{3}{4(x - 4)}\)
Specify the restrictions on the variable. (Select all that apply.) x ≠ 4 x ≠ 16 x ≠ 0 x ≠ 3 x ≠ 9 (Which one would be the answer?) @Hero
Which one do you think would be the answer? Remember, the denominator cannot equal zero.
I think it was 3 & 4
What do you mean 3 and 4? There's only one value that x cannot equal. Which is it?
0? I missed school when this was taught, I have no idea, sorry.
\[4x - 16 \ne 0\] Solve that to find out what x cannot equal
4
Is that the correct answer? @Hero
\[x \ne 4\] is correct, yes
Ok, thank you...the next question, I think I got the answer, but can you see if it's correct for me, please?
The answer is incorrect, I don't think the answer is all the way reduced. @ganeshie8 care to help?
which question ?
No, it is, I just factored it too much
The correct answer is \[\frac{3(x - 3)}{4(x - 4)}\]
oooooh ! ok Thank you lol I think I had that but didnt understand the second part
The rational expression in question not like below, right ? \(\dfrac{1}{(3x-9)(4x-16)}\)
no, the 3x-9 is on top.
good, then \(\dfrac{3(x - 3)}{4(x - 4)}\) is the final simplified form
this expression goes crazy when the denominator stuff equals \(0\)
So, to get the restrictions : set the denominator equal to \(0\), and solve the variable
Ok, hopefully, I'll remember lol
:) thats one important thing to keep in mind when u deal with solving equations involving rational expressions.
Ok, thank you...Can you help me with the other problem i tagged you in?
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