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OpenStudy (anonymous):
what is the [H3O+] in a solutionof 0.000500M NaOH
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OpenStudy (gebooors):
NaOH is diluted to water and [OH-] = 0.000500 M pOH = - log[OH-] = 3.301. Note that you have three significant numbers which are after decimal point in this case. then pH + pOH = 14 (in 25 degrees of C) [H3O+] = 10^(-pH)
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