If f'(x)'=\[\sin (\frac{ \pi e^X}{ 2 }\] and f(0)=1, then f(2)=?
Sorry, having a rough time trying to get this integral to something that can actually be done. What level of math is it from? It'll help me narrow down my choices.
I', taking culculus
So, I can't come up with a good answer myself, but I found a resource that addresses this problem specifically: http://math.stackexchange.com/questions/297036/if-fx-sin-frac-pi-ex2-and-f0-1-what-is-f2
Well \[ f(2)-f(0) =\int\limits_0^2 f'(x)\;dx= \int\limits_0^2\sin\left(\frac{\pi e^x}{2}\right)dx \]So since \(f(0) =1\) we can say: \[ f(2) = 1+\int\limits_0^2\sin\left(\frac{\pi e^x}{2}\right)dx \]
How can u do it....I don't get the step that u did....like...why u did f(2)-f(0)
did u using Fundamental theorem
so then f(2)= 1 ...right
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