Question

How many real numbers are in this equation?
\[0=-3x^2+x-4\]

Answer 1

\[0=-3x^2+x-4\]

Answer 2

use the discriminant to check

\[b^2 - 4\times a \times c\]

you have b = 1, a = -3 and c = -4

if < 0 then no real solutions

if = 0, or > 0 there are 2 real solutions...

Answer 3

So no real numbers?

Answer 4

that would be my guess since the discriminant is = -35

Answer 5

Thank you :)