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OpenStudy (anonymous):
OpenStudy (anonymous):
what is \(\frac{10}{5}\) ?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
k good so ignore C and D
OpenStudy (anonymous):
how about \[\frac{x^5}{x^2}\] ?
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OpenStudy (anonymous):
if it is not clear, let me know and i will tell you
OpenStudy (anonymous):
oh 5 divded b 2 is
OpenStudy (anonymous):
2.5
OpenStudy (anonymous):
ok not quite
OpenStudy (anonymous):
\[x^5=x\times x\times x\times x\times x\] and \[x^2=x\times x\] so
\[\frac{x^5}{x^2}=\frac{x\times x\times x\times x\times x}{x\times x}\]
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OpenStudy (anonymous):
OH OK
OpenStudy (anonymous):
is it B
OpenStudy (anonymous):
then cancel two of the \(x\)'s\[\frac{x^5}{x^2}=\frac{\cancel{x}\times \cancel{x}\times x\times x\times x}{\cancel{x}\times\cancel x}\]
OpenStudy (anonymous):
why did we cancel
OpenStudy (anonymous):
because you have common factors top and bottom of \(x\)
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OpenStudy (anonymous):
oh
OpenStudy (anonymous):
like computing
\[\frac{5\times 5\times 5\times 5\times 5}{5\times 5}\]
OpenStudy (anonymous):
of course it is much easier just to use the law of exponents that says \[\large \frac{x^n}{x^m}=x^{m-n}\] i.e. when you divide, you subtract the exponents