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Mathematics 15 Online
OpenStudy (anonymous):

math picture Below

OpenStudy (anonymous):

OpenStudy (anonymous):

what is \(\frac{10}{5}\) ?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

k good so ignore C and D

OpenStudy (anonymous):

how about \[\frac{x^5}{x^2}\] ?

OpenStudy (anonymous):

if it is not clear, let me know and i will tell you

OpenStudy (anonymous):

oh 5 divded b 2 is

OpenStudy (anonymous):

2.5

OpenStudy (anonymous):

ok not quite

OpenStudy (anonymous):

\[x^5=x\times x\times x\times x\times x\] and \[x^2=x\times x\] so \[\frac{x^5}{x^2}=\frac{x\times x\times x\times x\times x}{x\times x}\]

OpenStudy (anonymous):

OH OK

OpenStudy (anonymous):

is it B

OpenStudy (anonymous):

then cancel two of the \(x\)'s\[\frac{x^5}{x^2}=\frac{\cancel{x}\times \cancel{x}\times x\times x\times x}{\cancel{x}\times\cancel x}\]

OpenStudy (anonymous):

why did we cancel

OpenStudy (anonymous):

because you have common factors top and bottom of \(x\)

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

like computing \[\frac{5\times 5\times 5\times 5\times 5}{5\times 5}\]

OpenStudy (anonymous):

of course it is much easier just to use the law of exponents that says \[\large \frac{x^n}{x^m}=x^{m-n}\] i.e. when you divide, you subtract the exponents

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