Question

solve using the quadratic formula: x^2-6x+13=0

Answer 1

i know it goes into\[\frac{ 6\sqrt{-6^2+4*1*13} }{ 2*1 }\]

Answer 2

but I cant get the answer

Answer 3

\[
\Delta=b^2-4 a c= 36 -52=-16 <0 \implies 2 \text {complex roots} \\
x=\frac { 6\pm i\sqrt{16}}{2}=3\pm 2i


\\

\]

Answer 4

thank you!

Answer 5

YW