Question

Find the center, vertices, and foci of the ellipse with equation 2x2 + 8y2 = 16.

a. Center: (0, 0); Vertices:(0,-2squareroot2)(0,2squareroot2) ; Foci: (0,-squareroot6)(0,squareroot6)

b. Center: (0, 0); Vertices: (-8, 0), (8, 0); Foci: (-2squareroot15,0) (2squareroot15,0)

c. Center: (0, 0); Vertices: (0, -8), (0, 8); Foci: (0,-2squareroot15),(0,2squareroot15)

d. Center: (0, 0); Vertices:(-2squareroot2,0)(2squareroot,0) ; Foci: (-squareroot6,0)(squareroot6,0)

Answer 1

anyone?

Answer 2

opt d

Answer 3

eq is:x^2/8+y^2/2=1
a=2sqrt2,b=sqrt2
vertices=(+-a,0)=(+-2sqrt2,0)
foci=(+-ae,0)
e=sqrt3/2
so foci=(+-sqrt6,0)

Answer 4

thx so much!