matrix multiplication
ok let's begin first with the general rule of matrix multiplication
\[\left[\begin{matrix}a & b \\ e & f \end{matrix}\right] * \left[\begin{matrix}a' & b' \\ e' & f' \end{matrix}\right]=\left[\begin{matrix}aa'+be' & ab'+b f' \\ ea'+fe' & feb'+ff' \end{matrix}\right]\]
so would it be B
so we take the first line of the matrix on left and we multiply it with the first colonn of the second matrix such that the first element of the line is multiplied by the first element of the colonn we too and the second elements of the line multiplide by the second elements of the colonn and so on
ok let's do the maths :)
okay(: one sec let me figure it out!
sorry your problem is not muliplcation problem so it will be simple !
I though it's A*B but it's only -5A+4B
\[s*\left[\begin{matrix}a & a \\ c & d\end{matrix}\right]=\left[\begin{matrix}sa & sb \\ sc& sd\end{matrix}\right]\]
so calculate first -5*A and then 4*B I'll give you the answer and then compare it with yours okay
would it be C?
\[-5*A=\left[\begin{matrix}-30 & -5 \\ 20 & 30 \\ -35 & 35\end{matrix}\right]\]
\[4*B=\left[\begin{matrix}-20 & -4 \\ -12& -24 \\ 24 & 32\end{matrix}\right]\]
so now the addition and tell wich answer is correct
@hidy it is a multiplication problem, it just isn't a multiplication of a matrix by a matrix, rather a matrix by a scalar...
im so confused
yes @whpalmer4 you're right! it's multiplication by a scalar :)
okay I'll give you the addition rule \[\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]+\left[\begin{matrix}e & f \\ g & h\end{matrix}\right]=\left[\begin{matrix}a+e & b+f \\ c+g& d+h\end{matrix}\right]\]
so all you have to do is to add -5*A to 4*B
@kaylaelizabeth is there something not clear ?!!
I am writing the promems down on paper to do it I asked if it was c and you just keep giving me how to do it
ok good so you know how to do it and your answer is correct it's C :)
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