I GIVE MEDALS AND FAN!!!!!!!!!!!!!!!!!! Solve for t. 10,000= 39,145 (1+0.03/ 12)^12T
Lets start by dividing both sides by 39145
and then one side cancels out right?
Well the 39145 on the right cancels out yes...so what do you have after you do that?
divide 39145 by 10000
Other way around...divide 10000 by 39145
i got 0.255460467. would i round ?
\[\large \frac{10000}{39145} =\cancel{\frac{39145}{39145}}(1 + \frac{0.03}{12})^{12T}\] Yeah we can round that to .255 for now :) so we now have \[\large .255 = (1 + \frac{0.03}{12})^{12T}\]
((((240.743759253/6)*2)+20)-100)=your answer, (simplified it/hid it, you still have to work for it)
don't use google, it rounds too much
do i divide 0.03 and 12 ?
Now lets simplfy that stuff in the parenthesis... What is .003 / 12 ? and then add 1
Sorry 0.03 / 12
i got 1.0025
its less than 0.5 t<0.5
Perfect...so now we have \[\large .255 = (1.0025)^{12T}\] Now...we insert Logarithms...have you worked with them before?
yes but i dont understand them...
That okay...so 1 rule to remember *that we will use here* is \[\large lna^x = x \times lna\] meaning when you take the og of something with a variable as the exponent......that exponent comes down and multiplies to the log So here... \[\large ln(.255) = 12T \times ln(1.0025)\]
so i would find the log of .255 & 1.0025?
Not quite...now you divide both sides by ln(1.0025) because we want to isolate that 12T right? so \[\large \frac{ln(.255)}{ln(1.0025)} = 12T\] Right?
so now i can find the log or do i didvide them?
Well both ...unless you have a calculator of course then just input them :)
okay i got -547.2796551 o:
Haha don't freak out...that's correct :) Just 1 more step though... \[\large -547.2796551 = 12T\] To solve for 't' we divide both sides by 12....so T = ?
LOL okay c: T=-45.60663793
And there is your answer :) * I checked it it's right ;P
Thanks!
Hope that all made sense hun :)
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