Question

The rectangular loop shown in the figure moves at constant velocity normal to a stationary and uniform magnetic field. Determine the electromagnetic force induced across a small gap created in the loop. The loop sides are a and b.

Answer 1

Hai Sweet Friend, @meehee WeLcoMe to OpeN stuDy.. !!

>> Dear friend where is the figure ?
In usual cases, Since the loop remains within the field, there is no flux change across the loop over time, and also no net voltage/current induced in the coil. Hence, the EMF is zero.

Once the coil leaves the field, then apply
Faraday’s Law of induction:
ɛ = ∆ϕ / t
= ∆BA / t
= (50E-3 x 5E-2 x 15E-2) / (5E-2 / 7.5)
ɛ = 3.75E-4 / 6.67E-3
ɛ = 5.62E-2 Volts

So, accordingly comes your solution too for ( unknown points-no figure) A and B.

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