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Algebra
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OpenStudy (anonymous):
Solve for X algebraically:
3^(2X) + 3^(X+1) - 4 = 0
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OpenStudy (anonymous):
This involves logarithms because you are solving for the exponent in both of them to solve for x.
OpenStudy (anonymous):
First we need to rewrite equation
OpenStudy (anonymous):
\[(3^x)^2 + 3^x*3-4=0\]
OpenStudy (anonymous):
Are you getting this ???
OpenStudy (anonymous):
Hi, thank you for the response.
Does the +1 in the exponent become *3 ?
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OpenStudy (anonymous):
You could have solved this with logarithms.
OpenStudy (anonymous):
yes correct
Now we need to substitute 3^x = m ( any variable ) so can you try to rewrite equation ??
OpenStudy (anonymous):
Like a U substitution with U= 3^X ?
OpenStudy (anonymous):
How you got 12 ? we just need to replace 3^x by U okay ??
OpenStudy (anonymous):
U^2 + U *3 -4 =0 ???
??????
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OpenStudy (anonymous):
Perfect
Now we have to solve this quadratic equation can you try ?
OpenStudy (anonymous):
It isn't in standard form.
I don't know what to do with the part with: *3 -4
OpenStudy (anonymous):
you can use quadratic formula for it can you try ?
OpenStudy (anonymous):
Hello .... ????
OpenStudy (anonymous):
what would be C ?
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OpenStudy (anonymous):
X would be equal to 0.
OpenStudy (anonymous):
x = –1, 3.
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