Solve for X algebraically: 3^(2X) + 3^(X+1) - 4 = 0
This involves logarithms because you are solving for the exponent in both of them to solve for x.
First we need to rewrite equation
\[(3^x)^2 + 3^x*3-4=0\]
Are you getting this ???
Hi, thank you for the response. Does the +1 in the exponent become *3 ?
You could have solved this with logarithms.
yes correct Now we need to substitute 3^x = m ( any variable ) so can you try to rewrite equation ??
Like a U substitution with U= 3^X ?
How you got 12 ? we just need to replace 3^x by U okay ??
U^2 + U *3 -4 =0 ??? ??????
Perfect Now we have to solve this quadratic equation can you try ?
It isn't in standard form. I don't know what to do with the part with: *3 -4
you can use quadratic formula for it can you try ?
Hello .... ????
what would be C ?
X would be equal to 0.
x = –1, 3.
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