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Mathematics 18 Online
OpenStudy (anonymous):

Need help solving an equation fan and medal!

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[y = \sqrt{3x+3}\]

OpenStudy (anonymous):

wht are the options

OpenStudy (anonymous):

can you solve without options or no

OpenStudy (anonymous):

i got 6

OpenStudy (anonymous):

all the options are solving for x and they all have a bigger than or equal to sign and stuff

OpenStudy (anonymous):

or smaller than or bigger than or smaller than or equal to

OpenStudy (anonymous):

|dw:1398205512849:dw|

OpenStudy (anonymous):

6 isnt a option

OpenStudy (anonymous):

@katragaddasaichandra

OpenStudy (anonymous):

@suyogsomavanshi

OpenStudy (anonymous):

For what we are ask to solve it ???

OpenStudy (anonymous):

what is the domain of the function it says

OpenStudy (anonymous):

okay y = (3x+3)^(1/2) Are you familiar with domain ??

OpenStudy (anonymous):

not really

OpenStudy (anonymous):

Domain is set of all real values of x for which function does exist getting ???

OpenStudy (anonymous):

ok so how do you change the function into domain

OpenStudy (anonymous):

Hello?

OpenStudy (anonymous):

yes i know how to change the domain

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=sqrt+3x+%2B3

OpenStudy (anonymous):

That doesnt have domain?

OpenStudy (anonymous):

scroll down

OpenStudy (anonymous):

it says 0 all my options are -1 or 1

OpenStudy (anonymous):

the calc is correct remember

OpenStudy (anonymous):

Here we are having radical sign correct ?

OpenStudy (anonymous):

Yes at the start but all my options are greater than or equal to greater than less than and less than or equal to

OpenStudy (anonymous):

If there is negative sign under radical so it would becomes imaginary correct ???

OpenStudy (the_fizicx99):

3x + 3 ≥ 0 -3 -3 3x ≥ -3 /3 /3 x ≤ -1 (-∞,-1)

OpenStudy (anonymous):

there isnt a negative sign in the equation

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