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Mathematics 17 Online
OpenStudy (anonymous):

PLEASE HELP OMGOMG

OpenStudy (anonymous):

The zeros are at -5, -1, 4, 7 (the 4 is a guess, the picture is a bit small) and the possible multiplicities are: -5: multiplicity 2 -1: multiplicity 1 -4: multiplicity 1 -5: multiplicity 1 Any time the graph crosses the x-axis the multiplicity is odd and any time it touches the axis without crossing it's even. Since we don't have any other information we jsut use 1 and 2 for our odd and even numbers.

OpenStudy (anonymous):

{FIXED ANSWER} The zeros are at -5, -1, 4, 7 (the 4 is a guess, the picture is a bit small) and the possible multiplicities are: -5: multiplicity 2 -1: multiplicity 1 4: multiplicity 1 7: multiplicity 1 Any time the graph crosses the x-axis the multiplicity is odd and any time it touches the axis without crossing it's even. Since we don't have any other information we jsut use 1 and 2 for our odd and even numbers.

OpenStudy (anonymous):

Oh hold on: It tells you its a 7th degree. So the multiplicities need to add up to 7. I didn't read that part: SO: To get them to add up to seven were going to have to make some of them bigger, but they need to keep their odd or even. So, this works (2+3+1+1=7) -5: multiplicity 2 -1: multiplicity 3 4: multiplicity 1 7: multiplicity 1 This would also work: (4+1+1+1=7) -5: multiplicity 4 -1: multiplicity 1 4: multiplicity 1 7: multiplicity 1

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