Question

Find the angle between the 2 Vectors:

u=<2,-3> v=<1,-2>

Answer 1

Now we should use this formula

\[\alpha=arcos\left(\frac{\overrightarrow{u}\cdot\overrightarrow{v}}{||\overrightarrow{u}||*||\overrightarrow{v}||}\right)\]

\[\overrightarrow{u}\cdot\overrightarrow{v}=2*1+(-3)*(-2)\]

\[\overrightarrow{u}\cdot\overrightarrow{v}=8\]

\[||\overrightarrow{u}||=\sqrt{2^2+(-3)^2}=\sqrt{13}\]

\[||\overrightarrow{v}||=\sqrt{1^2+(-2)^2}=\sqrt{5}\]

replace this values

\[\alpha=arcos\left(\frac{8}{\sqrt{13}*\sqrt{5}}\right)\]

\[\boxed{\boxed{\alpha\approx0.78\approx44.78^o}}\]

Answer 2

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Answer 3

;D