Question

(3+square root 6)(3-square root 6)

Answer 1

?

Answer 2

\[(3+\sqrt{6}) \times (3-\sqrt{6})\]

Answer 3

can you simplify from there?

Answer 4

no

Answer 5

does it want you to simplify or solve?

Answer 6

simplify

Answer 7

Ok then, let me think.

Answer 8

use FOIL - first, outside, inside, last. (for binomials)

\[(6 -3\sqrt{6} + 3\sqrt{6} + -\sqrt{12})\]

Answer 9

Combine like terms

\[(6 -\sqrt{6} -\sqrt{12})\]

Answer 10

And i can't remember how to simplify from there sorry >.<

Answer 11

@SolomonZelman can you help?

Answer 12

\(\LARGE\color{blue}{ \bf (a+b)(a-b)=a^{2}-b^2}\)

your "a" is 3, and your "b" is √6 .

Answer 13

ok

Answer 14

now, @iminlove_123 please show me the steps.

Answer 15

im cinfused

Answer 16

Substitute 3 for "a" and sqrt{6} for "b"

Answer 17

\(\Large\color{blue}{ \bf (3-\sqrt{6}) (3+\sqrt{6})=3^{2}-(\sqrt{6}) ^{2}=9-6=3 }\)

Answer 18

oh ok i get it

Answer 19

you would get \[(3 + \sqrt{6}) \times (3 - \sqrt{6}) = 3^{2} - \sqrt{6}^{2}\]

Answer 20

Dang message me back