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I'll give a medal... Ideal Gas Law- If I contain 3 moles of gas in a container with a volume of 60 liters and at a temperature of 400 K, what is the pressure inside the container? (Answer: 1.64 atm)
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use PV=nRT
I tried that but I still can't get the answer for some reason...
P*(60 L)=(3moles)*(0.08206 atm*L/mol*K)(400 K) \(P=\dfrac{(3moles)*(0.08206~ atm*L/mol*K)(400~ K)}{(60 ~L)}\)=1.6412 atm
@aaronq can you fan me please?
Thank you so much
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no problem, do you see where you went wrong?
Yeah it was a silly mistake :P
haha good stuff
Yeah haha it caused so much frustration ;-;
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