(5/5x-1)-(1/1-5x)
\[\frac{5}{5x - 1} - \frac{1}{1 - 5x}\] Do you know what to do first?
not sure...been out of school way too long. im just trying to help a friend with her homework
When subtracting fractions, the denominators must be the same before subtracting.
Can you think of a way to make both denominators the same?
What if we re-wrote it this way: \[\frac{5}{5x - 1} - \frac{1}{-5x + 1}\] Do you see anything we can do from there?
they cancel each other out so its just 5-1 right?
Actually, the next step is to do this: Factor out a negative: \[\frac{5}{5x - 1} - \frac{1}{-(5x - 1)}\] Then this: \[\frac{5}{5x - 1} - \left(-\frac{1}{(5x - 1)}\right)\] To get this \[\frac{5}{5x - 1} + \frac{1}{5x - 1}\] Now the denominators are the same and you can add. So solving this is a matter of how well you are able to play with negatives.
is the final answer 6/10x-2
Remember, when adding fractions you only add the numerators. The denominator remains the same.
6/5x-1
6/(5x - 1)
That's how you write it horizontally. Vertically you write it like this: \[\frac{6}{5x - 1}\]
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