Question

use the quadratic formula to solve the equation: -3x^2-4x+10=0.... can you please sho me the working

Answer 1

\[ax ^{2}+bx+c=0\]
\[(-b \pm \sqrt{b ^{2}-4ac})/2a\]

Answer 2

just plug in the the numbers to the corresponding letters

Answer 3

huh

Answer 4

-3=a
-4=b
10=c

plug those into the second formula i gave you to get the answer

Answer 5

i did that already

Answer 6

so what did you get

Answer 7

i don't know what else to do

Answer 8

ok, well, the answer is -2.6103, and 1.2769839

Answer 9

how is that

Answer 10

(4+sqrt136)/-6 and (4-sqrt136)/-6

Answer 11

2x^2+9x=5
a=2 b=9 c=-5
x=-9+squareroot 9^2-4(2)(-5) all over 2(2)
x=-9+squareroot 81+40 over 4
x=-9+squareroot 121 over 4 =9+11 over 4
1 solution=- 9+11 over 4=1/2
2 solution= -9-11 over 4=-20/4 =-5

Answer 12

like that

Answer 13

yea

Answer 14

work out the next 1 like that

Answer 15

is anyone there

Answer 16

if your asking about 2x^2+9x=5 then your answer looks good to me

Answer 17

am talk about -3x^-4x+10=0

Answer 18

am stuck there