Question

http://prntscr.com/3cv4cz can you please help me solve this division?

Answer 1

This seems to be a case of polynomial division. I recommend filling out any missing degrees of x with 0x^n so we keep things straight.

\( x^2 + 0x + 3 \quad /\overline{ x^3 + 0x^2 - 3x + 7} \)

Are you familiar with the procedure?

Answer 2

yeah

Answer 3

i forgot to put that 0X^2 though

Answer 4

and that 0X on the left

Answer 5

Even though they are 0 right now, we have to be wary that they are still there. The terms may end up creating content over those. :)
Think you can figure it out with that then?

Answer 6

it looks quite long now on the left but ill try

Answer 7

so is this right? http://prntscr.com/3cv7r5

Answer 8

Yup, that's what I was getting as well.
So the quotient can now be rewritten as:
x + (-6x + 7)/(x^2 + 3)

Answer 9

oh i see

Answer 10

ok so im being asked when doing that division what will be the grade of the quotient and the remainder ?

Answer 11

i guess both are grade 1 right?

Answer 12

Yeah, the remainder also determines the grade of the original quotient so they are the same m=1. :)

Answer 13

what you mean by m=1?

Answer 14

Grade, or slope as I normally think of it. :p
From a line equation y = mx + b

Answer 15

the variable not so important, but that it is 1 is what we need to know.

Answer 16

hmm my friend but wouldn't be 2 and 1 grade polynomials like this http://prntscr.com/3cvai6?

Answer 17

Oh hang on, I was confusing the term quotient with the original fraction as a whole, not just what we ended up with on top.
Quotient was x, having grade 1
Remainder was -6x + 7, I was assuming grade and slope are synonymous? or -6 in this case?

Answer 18

yeah -6 would be the slope and the grade 1 right,,, so then both quotient and remainder are grade 1 !!!!

Answer 19

I was thinking that grade was the same as slope http://en.wikipedia.org/wiki/Grade_(slope)
You know grade to be the same as the highest power in the polynomial? If that is something you know to be true, then I agree.

Answer 20

yeah i was refering to the highest power of polynomial !!!! thanks for your time my friends

Answer 21

You're welcome! Alright, I see then. :)