Question

How do I convert 1.24 x 1024 molecules AgCH3COO (molecular weight 167 g/mol) to grams. will medal and fan!

Answer 1

@JJHSstudent

Answer 2

you wanna use \(n=\dfrac{N}{N_A}\) and \(n=\dfrac{m}{M}\)

n=moles
N=molecules
\(N_A\)= avogadro's number
m=mass
M=molar mass

Answer 3

I have n=2.08 what would be the next step? I got that from \[n=\frac{ N }{ N _{a} }\]

Answer 4

so first find the moles, n (with that formula)

then use the second to find the mass

Answer 5

So I would do n*M=m?

Answer 6

yes

Answer 7

thanks!

Answer 8

just to check m=347.36?