Question

Conduct an experiment of throwing two dice. Find the probability that the sum of the two dice is 2.

a. 1/36 = 0.03
b. 1/18 = 0.06
c. 1/12 = 0.08
d. 1/9 = 0.11

Answer 1

hmm im guessing this is a 6 sided dice?

Answer 2

I think so! @undeadknight26

Answer 3

hmm sadly i must go rest...i just found out like 2 seconds ago...
@agent0smith @AccessDenied @whpalmer4 @Destinymasha guys can help?

Answer 4

1/6 *1/6 = 1/36

Answer 5

1

Answer 6

Why is it that the answer? how did you made it? @jN7

Answer 7

you need to roll a 1 on both dice to get 2, the probability of getting a 1 on a roll is 1/6, therefore 1/6 * 1/6 =36

Answer 8

sorry typo, 1/6*1/6=1/36

Answer 9

If the problem were more complicated, such as rolling a sum divisible by 3, I would recommend a table. The table would represent all possible combinations you can roll.

Label the columns 1 through 6 and the rows 1 through 6. The box corresponding to one row and one column you would write the sum of the row value and column value. The total boxes would be 6x6 = 36. You then highlight the boxes that support the probability (in this case, one box row 1 col 1 has entry 2). Take the division: 1 (number of wanted outcomes) divided by 36 (total outcomes).
6
5
4
3 4 ...
2 3 4 ...
1 (2) 3 4 ...
1 2 3 4 5 6

Again, it is extraneous for this problem although it can be more useful for different types of questions. "Sum greater than 6, etc."

Answer 10

Here are all the possible rolls of 2 6-sided dice:
\[\begin{array}{cccccc}
\{1,1\} & \{1,2\} & \{1,3\} & \{1,4\} & \{1,5\} & \{1,6\} \\
\{2,1\} & \{2,2\} & \{2,3\} & \{2,4\} & \{2,5\} & \{2,6\} \\
\{3,1\} & \{3,2\} & \{3,3\} & \{3,4\} & \{3,5\} & \{3,6\} \\
\{4,1\} & \{4,2\} & \{4,3\} & \{4,4\} & \{4,5\} & \{4,6\} \\
\{5,1\} & \{5,2\} & \{5,3\} & \{5,4\} & \{5,5\} & \{5,6\} \\
\{6,1\} & \{6,2\} & \{6,3\} & \{6,4\} & \{6,5\} & \{6,6\} \\
\end{array}\]
If you count them, you'll see that there are 36 possible rolls, and only 1 of them produces a sum of 2 (affectionately known as "snake eyes" by the craps players among us)
so the probability is 1/36.