Need help finding order and degree for the question below:
\[\LARGE [\dfrac{d^2y}{dx^2}+\dfrac{dy}{dx}]^{3/2}=y\] My doubt is why squaring does not give me the required answer?
well, if you square does it rid you of the exponent on your differentials?
(3/2)*2=1 so yeah?
check your math real quick
lol did I make a silly mistake? :O
yea, (3/2)*2=3
but def have the right idea
So then I get order 2 and degree 3?
that's what I'm getting
But the solution given is raising power to 2/3 and hence order 2 and degree 1.
well, you could do that too. Which is simpler
usually you want the simplest form for the canonical
But I need a real reason to justify the actual answer.
Oh, well you want to reduce it as much as possible to make it easiest to solve. Eradicating the degree, makes the problem easier
technically both could be correct, but the simplest form is degree 1 and order 2
hmm..I am still not satisfied :| maybe I should add simplest form to the definition of degree in my notes.
let me see if I can dig up a good reason
Thanks :)
So side note: This is really awesome quick reference I found http://www.sosmath.com/tables/diffeq/diffeq.html Also check out how to solve ODEs using complex variables, it's pretty sick method.
That doesn't explain finding order. It is about solving differential equations.
I know, but I just liked it for future reference. Here is a new book you could take a look at, but unfortuanately, I am unable to find any similar examples that make it easier other than adjusting the prompt to determine the simplest order and degree of the following dif eq. http://www.textbooksonline.tn.nic.in/books/12/std12-bm-em-2.pdf
Okay thanks for trying
np, but I would just say do reduce the polynomial as much as possible since you are unable to have mixed derivatives and be able to solve
ie Y''Y' is not ok, which if you have any sort of power on that particular problem, would exist
Maybe that would be an adequate reason to get rid of the exponent completely
Have you tried using Conflict Resolution skills on your equation?
The order is the highest derivative, here it's 2. The degree is the power on the highest derivative. Since it's not in that form, you have to arrange it to algebraically show that. \[(y''+y')^{3/2}=y\] \[y''+y'=y^{2/3}\]This is the form you need. If you only square root both sides and then make it look like this by multiplying out the cube, it's wrong because your second derivative isn't isolated. \[(y'')^3+3(y'')^2y'+3y''(y')^2+(y')^3=y^2\] There's no power on "the" highest derivative since it's spread out among 3 terms. So the degree is 1 here.
Oh now that makes sense. Thanks a lot @Kainui and @FibonacciChick666
Can I get a "thank you."
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