could you explain maxima and minima value of cos(cosx)
If u look at the Cosine graph, you will see that it reaches it's maxima at values of x = 0, 2Pi, 4Pi... even multiples of Pi... Cos x varies from -1 to 1 (both inclusive) So, for the maximum value of Cos(Cos x), I should get Cos x as near to 0 (or any even multiple of Pi) as possible... That is, get X as near to Pi/2 as possible... This is possible for x =Pi/2... So For x = Pi/2, Cos x is 0 So maximum value is Cos 0 = 1
I would just take the derivative and set it equal to zero to find where slope is horizontal
\[\frac{d}{dx}cos(cosx) = sin(cosx)sinx\]
(negatives cancel)
sorry guys i could not understand.
I'm not sure I could explain this in any other way. Do you know calculus?
yes i know calculus.
Alright, so you know that 1st derivative of a function is slope. When slope is horizontal, i.e., 0, then you are either at a max or min on the curve
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imagine they are horizontal lines
tangent lines to the curve
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