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Mathematics 23 Online
OpenStudy (anonymous):

could you explain maxima and minima value of cos(cosx)

OpenStudy (anonymous):

If u look at the Cosine graph, you will see that it reaches it's maxima at values of x = 0, 2Pi, 4Pi... even multiples of Pi... Cos x varies from -1 to 1 (both inclusive) So, for the maximum value of Cos(Cos x), I should get Cos x as near to 0 (or any even multiple of Pi) as possible... That is, get X as near to Pi/2 as possible... This is possible for x =Pi/2... So For x = Pi/2, Cos x is 0 So maximum value is Cos 0 = 1

OpenStudy (anonymous):

I would just take the derivative and set it equal to zero to find where slope is horizontal

OpenStudy (anonymous):

\[\frac{d}{dx}cos(cosx) = sin(cosx)sinx\]

OpenStudy (anonymous):

(negatives cancel)

OpenStudy (anonymous):

sorry guys i could not understand.

OpenStudy (anonymous):

I'm not sure I could explain this in any other way. Do you know calculus?

OpenStudy (anonymous):

yes i know calculus.

OpenStudy (anonymous):

Alright, so you know that 1st derivative of a function is slope. When slope is horizontal, i.e., 0, then you are either at a max or min on the curve

OpenStudy (anonymous):

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OpenStudy (anonymous):

imagine they are horizontal lines

OpenStudy (anonymous):

tangent lines to the curve

OpenStudy (anonymous):

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