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e^x+5=2
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what to find?
solve the exponential equation. Express the solution set in terms of natural logarithms
is the question 1. \[e^{x + 5} = 2\] or 2. \[e^x + 5 = 2\]
1
ok... so take the ln of both sides and you have \[\ln(e^{x + 5}) = \ln 2\] applying the index law for logs it becomes \[(x + 5)\ln(e) = \ln(2)\] and now you need to know...that \[\log_{a} (a) = 1\] so applying that law to this question you have \[(x + 5) \times 1 = \ln(2)\] now you should be able to solve for x hope it helps
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x=ln2-5????
There exists no x that satisfies the equation.
what the answer then
|dw:1398336741354:dw|
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