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Mathematics 25 Online
OpenStudy (anonymous):

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x4 + 4x3 + 3x2 + 18

OpenStudy (tkhunny):

Well, do it. What are ALL the factors of 18? That's where you start.

OpenStudy (anonymous):

okay im reaaly confused on this. completly lost. can u help me solve it.

OpenStudy (tkhunny):

I did. Find ALL the factors of 18. ALL of them.

OpenStudy (anonymous):

factors can be 9 and 2??

OpenStudy (tkhunny):

And 1*18 And 3*6 ALL of them!

OpenStudy (anonymous):

18 and 1

OpenStudy (tkhunny):

Do you have them all? 1*18 2*9 3*6 Is that it?

OpenStudy (anonymous):

ya the factors are 1,3,6,9, and 18

OpenStudy (tkhunny):

Where did 2 go? Okay, that was the constant term. Now, we need to worry about the highest degree term, -2x^4 All the factors of 2 are 1 and 2. That was a little easier. The Rational Root Theorem states that Rational Roots, if they exist, are quotients of those two collections. In this case: \(\dfrac{Some\;Factor\;of\;18}{Some\;Factor\;of\;2}\). Can you build that entire collection?

OpenStudy (anonymous):

no u lost me there. so what do i divide. did u slove it?

OpenStudy (anonymous):

my test is timed i just really really need help solving it please! i attempted this 4 times already and got it wrong

OpenStudy (tkhunny):

All the factors of 18. These are 1, 2, 3, 6, 9, 18 All the factors of 2. These are 1, 2 All possible combinations with a factor of 18 in the numerator and a factor of 2 in teh denominator. I don't actually believe you cannot understand this. 1/1, 2/1, 3/1, 6/1, 9/1, 18/1, 1/2, 2/2, 3/2, 6/2, 9/2, 18/2 That's HALF the list. -1/1, -2/1, -3/1, -6/1, -9/1, -18/1, -1/2, -2/2, -3/2, -6/2, -9/2, -18/2 That's the other half. If there are rational roots, they MUST be among those listed. Never underestimate the power of something that can count!

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