Sketch the region enclosed by the lines: x = 0, x = 6, y = 2, and y = 6. 6. Find the area of the region.
Hints: Equations such as x = 0 and x = 6 represent vertical lines, and those such as y = 2 and y = 6 represent horizontal lines. Hope that helps you get started graphing this situation. a graph will help you visualize the length and width of this region. Later you'll be able to read off the length and the width of the region almost immediately, without a drawing or any but the simplest calculations.
How would I use those to graph the situation? If I knew how the get the lengths, I could solve the problem, no problem.
the lengths are the difference 6-0=6 and 6-2=4
So to find the area, 6*4=24?
\[x_2-x_1\] \[y_2-y_1\]
yes,but did you draw the shape
24 is correct
No, but I assume it's a square or rectangle.
rectangle
Oh yeah, the lengths are not equal. duh moment. oops.
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Very nice graph, @jonask! OrangeMaster: Just by "eye-balling" this sketch, you can probably tell that the length of this rectangle is 6 (that is, 6-0=6). What is the width of this rectangle? Consider this to be just a summary, because you've already indicated the area correctly: 4*6 = 24 square units.
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