Can somebody help me find the value for 'X' in this equation? 10^x-7 = 10^3x+8
is this the correct equation? \[10^{(x-7)}= 10^{(3x+8)}\] or \[10^{x}-7= 10^{3x}+8\]
The first one sir.
In that case - you can ignore the fact that they are exponents (x-7)=(3x+8)
Okay, could you show me the method to solving for x?
No - I won't show you that. If you are dealing with equations such as in your question then you must be able to solve the simple equation above. Simply move all x terms to one side, and constant terms to the other - taking note of the signs....
I'm sorry i'm still having a little trouble putting in the equation. Im not the best at this. Could you show me how the equation is the put together to solve?
I'm sorry - I believe that you must have the skills to solve this yourself x-7 = 3x+8
Add 7 to each side of the equation Then subtract 3x from each side of the equation
After that would the new equation would be x-11 = 7x+8 ?
start by adding 7 to each side of the equation
X-14 = 10x+8?
write the equation out as it is - but add "+7" to each side
x-7+7=3x+8+7
OK - now do the adding up of JUST the numbers on each side
x-14=3x+15?
Not quite right The right side is correct - but the left side is wrong x-7+7=3x+8+7 Try again
x7=3x+15
the 7 becomes positive?
sorry - you started by writing an equation involving exponents, but now cannot add -7+7 Are you focussed on doing this?? - I will not give oyu the answer...
Yeah, I am.
so - what is x-7+7 ??
0?
no start with x ... subtract 7 .... add 7 ....... what is left?
Im getting zero.
Have another think - when you don't get 0 come back
hint: x represents some unknown number - any unknown number.....
3?
I don't think oyu are in a position to proceed with this question. I can't see how oyu are asking questions of this sort without having already been able to solve an equation such as you have. I don't mean to discourage you - but you must work on some basic algebra (equations) before you can tackle this. Good luck
Okay. Thanks for the help anyways.
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