Question

Simplify the radical expression

sqrt{7}+3 sqrt{7}
a)2 sqrt{7}
b)4 sqrt{14}
c)4 sqrt{7}
d)2 sqrt{14}

Answer 1

if you have 1 square root of 7 and add 3 more square root of 7's how many sqr(7) do you have ?

Answer 2

if you work it out completly it is 11.37673

Answer 3

14

Answer 4

so would it be D?

Answer 5

try a simpler problem first:
you have 1 dog and add 3 more dogs, how may dogs?

you have 1 apple and add 3 more apples, how many apples ?

you have 1 sqr(7) and add 3 more sqr(7), how many sqr(7) ?

Answer 6

Oh, it's 4! Haha oops

Answer 7

and you write it as
\[ 4 \sqrt{7} \]
which means 4 sqr(7) or
\[ \sqrt{7}+ \sqrt{7}+ \sqrt{7}+ \sqrt{7} \]
either way, 4 of them

Answer 8

Okay, thanks so much!! Can you help me simply two other expressions?

Answer 9

lololol

Answer 10

\[2\sqrt{6+3\sqrt{96}}\]

Answer 11

Thats the next one I need help with

Answer 12

@phi

Answer 13

you should make it a new post, otherwise these things get a bit long.

but the first thing I would do is find all the prime factors of 96
can you do that ?

Answer 14

Hold on

Answer 15

1, 2, 3, 4, 6, 8, 12, 16, 24, 32,48, and 96. Right?

Answer 16

\[50\sqrt{1}\]

Answer 17

Are you sure its not \[50\sqrt{6}\]? beccause I don't have the answer choice of \[50\]

Answer 18

\[50\sqrt{1}\]

Answer 19

just the prime factors (prime numbers) that when you multiply them you get 96
you get 2*2*2*2*2*3

Answer 20

btw, is the problem
\[\sqrt[2]{6+\sqrt[3]{96}}\]
?

Answer 21

Ohh, okay.

Answer 22

So then what??

Answer 23

in other words is the cube root of 96 or 3 times the square root of 96 ?
\[ \sqrt[3]{96} \text{ or } 3 \sqrt{96} ? \]

Answer 24

No it's not

Answer 25

?
which is it ? can you post a screen shot ?

Answer 26

I have it posted up a little higher

Answer 27

I can't screenshot, but i will post the equation again quick. Hang on.

Answer 28

\[2\sqrt{6+3\sqrt{96}}\]

Answer 29

yes, I see the expression
\[ 2\sqrt{6+3\sqrt{96}} \]
but I want to know if you really mean 3 times sqrt(96) or cube root of 96
(and the same for the 2)

Answer 30

No, that's it.

Answer 31

ok. the sqr(96) is the same as sqr(2*2 * 2*2 * 2 *3)
"pull out pairs" from the square root, and "toss one of each pair"
\[ \sqrt{2\cdot 2 \cdot 2\cdot 2\cdot 2 \cdot 3}= 2\cdot 2 \sqrt{2 \cdot 3} \]
or
\[ 4 \sqrt{6} \]

Answer 32

and the problem is now
\[ 2\sqrt{6+ 3\cdot 4 \sqrt{6}} \]
or
\[ 2\sqrt{6+ 12 \sqrt{6}} \]

Answer 33

you mean \[14\sqrt{6}\]?

Answer 34

nvm, but I have the answer now

Answer 35

I need help with one more but I will make a different post of it and tag you in it

Answer 36

what is the answer for this one ? (out of curiosity)

Answer 37

I think it's c. :)