Can you help me with another problem? @ZeHanz

Question

anonymous · Answer

no

zehanz · Answer

OK

anonymous · Answer

$$\frac{ 9 }{ 3x - 1 } - \frac{ 5x }{ 2x + 3 }$$

zehanz · Answer

(sorry, connection was lost)

Now you have to subtract. This can only be done if the denominators are the same.
You can use the same trick as in $\dfrac{1}{3}-\dfrac{1}{5}$.

How would you do that one?

anonymous · Answer

Well that would be 15. So you would multiply the 3 by 5, and the 5 by 3, correct? Same with the numerators. Which would be 5/15 - 3/15  = 2/15

zehanz · Answer

So if you do the same with your fractions, the new denominator becomes (3x-1)(2x+3) and the numerators have to be: 9(2x+3) and 5(3x-1), okay?

zehanz · Answer

I mean this: $\dfrac{9(2x+3)}{(3x-1)(2x+3)}-\dfrac{5x(3x-1)}{(3x-1)(2x+3)}$

anonymous · Answer

Oh, okay got confused for a second there, haha xD

zehanz · Answer

Yeah, with the dfrac{}{} stuff it is clearer, but sometimes I'm lazy...

anonymous · Answer

Haha don't worry about it xD But what would I do now? Do I multiply 9 and 2x, 9 and 3, for the first one? And the 5x and 3x, 5x and -1?

zehanz · Answer

Yes, and then put everything in the numerator together.

zehanz · Answer

I have: 18x+27-15x²+5x. Now simplify this...

anonymous · Answer

Yeah that's what I got. And would it be $$\frac{ -15^{2} + 23x + 27}{ (3x - 1)(2x + 3) }$$

zehanz · Answer

I think you have got it right. Sadly, there is nothing to simplify anymore, because the numerator can't be factored.

zehanz · Answer

-15x², you meant :D

anonymous · Answer

Oh yes sorry xD

zehanz · Answer

I think you have done really well here! You understand fractions imo.

anonymous · Answer

I try my best ^-^