Question

parabolas

Answer 1

Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1

Answer 2

use the chart

Answer 3

so the verticies are going to be +-3,0

Answer 4

Correct ! graphing it may help :)

Answer 5

wait but the foci should be +-7 shouldnt it?

Answer 6

but my only answers are +-5,0 or +-3,0 :/

Answer 7

your hyperbola :

\(\large \dfrac{x^2}{9} - \dfrac{y^2}{16} = 1\)

Answer 8

which is same as :

your hyperbola :

\(\large \dfrac{x^2}{3^2} - \dfrac{y^2}{4^2} = 1\)

Answer 9

\(\implies a = 3, b = 4\)

Answer 10

So, vertices = \((\pm a, 0) = (\pm 3, 0) \)

Answer 11

Foci = \((\pm c, 0) = ?\)

Answer 12

Find \(c\), by using below relation :

\(c^2 = a^2 + b^2\)

Answer 13

oh okay that make sense c: