Question

Can someone please explain to me how to solve this problem?
6-4(3-5)^2+30÷5
Like I know the answer but I don't know the steps to solving it :/

Answer 1

You have to respect the order of operations: first calculate powers, then multiply and divide (no priority for either of them) then add and subtract (same here).

Brackets can change this: you have to calculate what is between them first.

So: 3-5=-2.

we then have 6-4*(-2)^2+30/5.

Powers first: (-2)^2=(-2)*(-2)=4, so:

6-4*(-2)^2+30/5 = 6-4*4+30/5.

Now multiply and divide:

6-4*4+30/5=6-16+6.

Now add and subtract (from left to right, no priority for + or -)

Answer: -4

Answer 2

YW!

Answer 3

thanks!! :)