Question

What is the slope of the line containing the point (0,-3) and tangent to the graph y=xln(x)?

Answer 1

I think you should use the fact that,
\[slope=f'(x)=y'\]

Answer 2

What would I do from there though? the graph doesnt have constant slope so couldnt this have multiple answers?

Answer 3

do you understand what the question is actually look for?

Answer 4

I think I do...Maybe not though. you you explain it?

Answer 5

so it's asking for the slope of that line. But to find it, you need to know what point on the graph that will yields to the requirement

Answer 6

In other words, find the value of a so that you can do f'(a)

Answer 7

But the point is (0,-3)

Answer 8

:O then just move the point down and the draw the tangent line of the graph passes through (0,-3)