Find the rectangular coordinates of the point with the polar coordinates (8, 3 divided by 2 pi).
i really hope it is \((8,\frac{2\pi}{3})\) and not what you wrote
not "3 divided by 2 pi" but rather "2 pi divided by 3" am i right?
noooo im sorry but its \[(8,\frac{ 3 }{ 2 }\pi)\]
ok that works too, 3 pi divided by 2
it is always true that \((r,\theta)\) has rectangular form \(x=r\cos(\theta), y = r\sin(\theta)\) in your case it will be \[x=8\cos(\frac{3\pi}{2}),y=8\sin(\frac{3\pi}{2})\] do you know how to evaluate those?
no .-.
do you know \(\cos(\frac{3\pi}{2})\)? if the answer is "no" i will show you how to find it
can you show me :D
find \(\frac{3\pi}{2}\) on the unit circle on the last page of the attached cheat sheet then look at the coordinates the first coordinate is cosine, the second coordinate is sine
let me know when you see it and what you get
so 270degrees so its 0,-1?
yes
so could the answer be 0,-8
that means \(x=8\times 0=0\) and \(y=8\times -1=-8\) so your point is \((0,-8)\)
yes
i beat you to it c: can i ask so more questions and tag you in them?
yes
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