Find the equation of the parabola with focus (5, 1) and directrix y = -1.

Question

anonymous · Answer

ok there you are
first lets draw a picture so we see what it looks like kinda

anonymous · Answer

ok .

anonymous · Answer

|dw:1398390524868:dw|

anonymous · Answer

the vertex is half way between the focus and the directrix
that means it is at $(5,0)$ 
also we see it opens up, so the $x$ term will be squared not the $y$ term

anonymous · Answer

general form is $$4p(y-k)=(x-h)^2$$ in your case $h=5,k=0$

anonymous · Answer

$p$ is the distance between the focus and the vertex, which is 1
so it is 
$$4y=(x-5)^2$$ done

anonymous · Answer

if you have multiple choice problem and don't see that answer, i could be written as 
$$y=\frac{1}{4}(x-5)^2$$ we can check it if you like

anonymous · Answer

my choices are :
(x-5)^2 = 4y 
(y-5)^2 = 4x 
(x-5)^2 = -4y 
(y-5)^2 = -4x

anonymous · Answer

$$4y=(x-5)^2$$ is the same as $$(x-5)^2=4y$$right?

anonymous · Answer

yes because a+z = z+a i think .

anonymous · Answer

can you help me with another one ?

anonymous · Answer

@satellite73

anonymous · Answer

sure post again